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26y^2-130y+156=0
a = 26; b = -130; c = +156;
Δ = b2-4ac
Δ = -1302-4·26·156
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-130)-26}{2*26}=\frac{104}{52} =2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-130)+26}{2*26}=\frac{156}{52} =3 $
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